discrete = truefalse

samplecount = posint

sampletime = positive

hertz = truefalse

The Square command generates a periodic square waveform.

By default, Square returns an expression representing the waveform. If the option discrete is assigned true, Square returns a Vector of data points.

The optional parameter yht specifies the height of the signal. Its default value is one.

The optional parameter f specifies the frequency of the waveform. The default is one. The units of f are determined by the keyword parameter hertz.

The optional parameter d specifies the duty-cycle of the square wave. A numeric value must be between 0 and 1, inclusive.

The optional parameter t0 specifies the start time of the waveform. Its default value is zero.

The optional parameter y0 specifies the initial value. Its default value is zero.

$\mathrm{with}\left(\mathrm{DynamicSystems}\right)\:$

$\mathrm{Square}\left(\right)$

$\left\{\begin{array}{cc}1& t-2\mathrm{\pi }\mathrm{trunc}\left(\frac{t}{2\mathrm{\pi }}\right)<\mathrm{\pi }\\ 0& \mathrm{otherwise}\end{array}\right.$

$\mathrm{Square}\left(\mathrm{yht}\&comma;f\&comma;d\&comma;\mathrm{t0}\&comma;\mathrm{y0}\right)$

$\left\{\begin{array}{cc}\mathrm{y0}& t<\mathrm{t0}\\ \mathrm{y0}+\left(\left\{\begin{array}{cc}\mathrm{yht}& t-\mathrm{t0}-\frac{2\mathrm{\pi }\mathrm{trunc}\left(\frac{\left(t-\mathrm{t0}\right)f}{2\mathrm{\pi }}\right)}{f}<\frac{2d\mathrm{\pi }}{f}\\ 0& \mathrm{otherwise}\end{array}\right.\right)& \mathrm{otherwise}\end{array}\right.$

${\mathrm{Square}\left(\mathrm{discrete}=\mathrm{true}\right)}^{\mathrm{\%T}}$

$\left[\begin{array}{cccccccccc}1.& 1.& 1.& 1.& 0.& 0.& 0.& 1.& 1.& 1.\end{array}\right]$

$\mathrm{plot}\left(\mathrm{Square}\left(2\&comma;\frac{3}{4}\&comma;\frac{1}{2}\&comma;0\right)\&comma;t=0..18\right)$