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Example 1.
First initialize a Lie algebra.
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Define a subspace , a complement , and an inner product on .
Alg1 >
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Check that , is naturally reductive with respect to
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Naturally reductive means that [i] the symmetric tensor defined by is invariant with respect to the vectors in and [ii] the Lie derivative of with respect to the vectors in vanishes on pairs of vectors from . Thus, for the above example we have:
Alg1 >
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Alg1 >
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| (2.3) |
Alg1 >
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| (2.4) |
Alg1 >
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| (2.5) |
Example 2.
In this example we consider a Lie algebra containing a parameter . We find that a certain subspace admits a naturally reductive complement when
First initialize a Lie algebra and display the Lie bracket multiplication table.
Alg1 >
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For we have that is a reductive complement. We let the inner product be arbitrary.
Alg2 >
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Alg2 >
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Alg2 >
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We see that the that span is naturally reductive only when . To check this we substitute into the Lie algebra data structure for L2 and change the name of the algebra to Alg3.
Alg2 >
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| (2.8) |
Alg2 >
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Alg2 >
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