$A≔\mathrm{GenerateSlope}\left(10\,0\,1\right)$

$A≔\left[\begin{array}{cccccccccc}0.& 1.& 2.& 3.& 4.& 5.& 6.& 7.& 8.& 9.\end{array}\right]$

$B≔\mathrm{GenerateSlope}\left(3\,0\,\mathrm{\pi }\right)$

$B≔\left[\begin{array}{ccc}0.& 3.14159265358979& 6.28318530717959\end{array}\right]$

$c≔\mathrm{Array}\left(1..10\,'\mathrm{datatype}'='\mathrm{float}'\left[8\right]\,'\mathrm{order}'='\mathrm{C\_order}'\right)\:$

$\mathrm{GenerateSlope}\left(10\,1.3\,-0.35\,'\mathrm{container}'=c\right)$

$\left[\begin{array}{cccccccccc}1.30000000000000& 0.950000000000000& 0.600000000000000& 0.250000000000000& \mathrm{-0.0999999999999999}& \mathrm{-0.450000000000000}& \mathrm{-0.800000000000000}& \mathrm{-1.15000000000000}& \mathrm{-1.50000000000000}& \mathrm{-1.85000000000000}\end{array}\right]$

$c$

$\left[\begin{array}{cccccccccc}1.30000000000000& 0.950000000000000& 0.600000000000000& 0.250000000000000& \mathrm{-0.0999999999999999}& \mathrm{-0.450000000000000}& \mathrm{-0.800000000000000}& \mathrm{-1.15000000000000}& \mathrm{-1.50000000000000}& \mathrm{-1.85000000000000}\end{array}\right]$

$\mathrm{GenerateSlope}\left(10\,1.3\,-0.35\right)$

$\left[\begin{array}{cccccccccc}1.30000000000000& 0.950000000000000& 0.600000000000000& 0.250000000000000& \mathrm{-0.0999999999999999}& \mathrm{-0.450000000000000}& \mathrm{-0.800000000000000}& \mathrm{-1.15000000000000}& \mathrm{-1.50000000000000}& \mathrm{-1.85000000000000}\end{array}\right]$

$\mathrm{SignalPlot}\left(\mathrm{GenerateSlope}\left(100\,1.3\,-0.35\right)\right)$