Chapter 5: Applications of Integration
Section 5.7: Centroids
Determine the centroid of the trapezoid 25 × 15 × 15 × 15 (feet), longest edge uppermost and horizontal.
By the Pythagorean theorem and Figure 5.7.5(a), the height h of the trapezoid is 152−52=102.
With respect to Figure 5.7.5(a), let point P be the origin of a Cartesian coordinate system. Then, the coordinates of points P,Q,R,S, are respectively,
The left and right edges of the trapezoid are given respectively by the equations
yL=−22 x and yR=22x−15
The area of the trapezoid is
Figure 5.7.5(a) 25 × 15 × 15 × 15 trapezoid
If x&conjugate0;,y&conjugate0; is the centroid, then x&conjugate0;=0 (by symmetry) and
y&conjugate0; = 12 A∫−50h2−yL2 ⅆx+∫015h2 ⅆx+∫1520h2−yR2 ⅆx=652/12 ≐ 7.66
Tools≻Load Package: Student Precalculus
Context Panel: Assign Name
Area of the trapezoid
Equations of the left and right edges
Apply the Line command from the Student Precalculus package.
Apply the formula y&conjugate0;=1A∫abf2x−g2x/2 ⅆx from Table 5.7.1
12 A∫−50h2−yL2 ⅆx+∫015h2 ⅆx+∫1520h2−yR2 ⅆx = 6512⁢2→at 10 digits7.660323461
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