The convert(procedure, algebraic) command converts a given procedure into its algebraic form, if possible. For example, the procedure z -> sin(z) + 1 is converted into sin + 1. Remember that in Maple 1(z) = 1.

When the conversion to the algebraic form is not possible, the received procedure itself is returned. For a conversion to be possible, the given procedure is expected to have a calling sequence, that is, be a procedure of some arguments, and return an algebraic expression of its arguments containing only constants or functions of the given arguments.

$z\mapsto \mathrm{\Gamma }\left(z\right)\cdot \mathrm{\Psi }\left(z\right)+1$

$z\mapsto \mathrm{\Gamma }\left(z\right)\cdot \mathrm{\Psi }\left(z\right)+1$

$\mathrm{convert}\left(\,\mathrm{algebraic}\right)$

$\mathrm{\Gamma }\mathrm{\Psi }+1$

$\left(a\,z\right)\mapsto f\left(a\,z\right)+\mathrm{\pi }$

$\left(a\,z\right)\mapsto f\left(a\,z\right)+\mathrm{\pi }$

$\mathrm{convert}\left(\,\mathrm{algebraic}\right)$

$f+\mathrm{\pi }$

$\left(a\,z\right)$

$f\left(a\,z\right)+\mathrm{\pi }\left(a\,z\right)$

$\mathrm{simplify}\left(\right)$

$f\left(a\,z\right)+\mathrm{\pi }$

$\left(\right)\mapsto \sin \left(z\right)$

$\left(\right)\mapsto \sin \left(z\right)$

$\mathrm{convert}\left(\,\mathrm{algebraic}\right)$

$\left(\right)\mapsto \sin \left(z\right)$

$z\mapsto f\left(1\,z\right)$

$z\mapsto f\left(1\,z\right)$

$\mathrm{convert}\left(\,\mathrm{algebraic}\right)$

$z\mapsto f\left(1\,z\right)$

$z\mapsto \frac{\mathrm{LambertW}\left(z\right)}{\left(1+\mathrm{LambertW}\left(z\right)\right)\cdot z}$

$z\mapsto \frac{\mathrm{LambertW}\left(z\right)}{\left(1+\mathrm{LambertW}\left(z\right)\right)\cdot z}$

$\mathrm{convert}\left(\,\mathrm{algebraic}\right)$

$z\mapsto \frac{\mathrm{LambertW}\left(z\right)}{\left(1+\mathrm{LambertW}\left(z\right)\right)\cdot z}$

$z\mapsto \frac{\mathrm{LambertW}\left(z\right)}{1+\mathrm{LambertW}\left(z\right)}$

$z\mapsto \frac{\mathrm{LambertW}\left(z\right)}{1+\mathrm{LambertW}\left(z\right)}$

$\mathrm{convert}\left(\,\mathrm{algebraic}\right)$

$\frac{\mathrm{LambertW}}{1+\mathrm{LambertW}}$